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NEET 2004 (AIPMT) · Electrostatic Potential Energy

Electrostatic Potential Energy question from NEET 2004 (AIPMT)

Q61NEET 2004 · AIPMTEasy

Electrostatic Potential Energy

A bullet of mass 2 g is having a charge of 2 $\mu$ C. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of 10 m/s?

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Answer: (b)

$qV = \dfrac{1}{2}mv^2$
$V = \dfrac{mv^2}{2q} = \dfrac{2\times10^{-3} \times 100}{2 \times 2\times10^{-6}} = 5\times10^4$ V
$V = 50$ kV. So the answer is (b).

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