A bullet of mass 50 g is fired with a speed 100 m/s on a plywood and emerges with 40 m/s. The percentage loss of kinetic energy is: (a) 44% (b) 16% (c) 84% (d) 32%

Answer: (c). K ∝ v², so fractional loss = 1 - (vf²)/(vi²). = 1 - (40/100)² = 1 - 0.16 = 0.84 So the answer is (c) 84%.

A bullet of mass 50 g is fired with a speed 100 m/s on a plywood and… | JEE Main 2024 (6 Apr, Shift 1)

Q6JEE Main 2024 · 6 APR · SHIFT 1Easy

Work-Energy Theorem

A bullet of mass $50\text{ g}$ is fired with a speed $100\text{ m/s}$ on a plywood and emerges with $40\text{ m/s}$ . The percentage loss of kinetic energy is:

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Answer: (c)

$K \propto v^2$ , so fractional loss $= 1 - \frac{v_f^2}{v_i^2}$ .
$= 1 - \left(\frac{40}{100}\right)^2 = 1 - 0.16 = 0.84$
So the answer is (c) $84\%$ .

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