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JEE Main 2024 (4 Apr, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2024 (4 Apr, Shift 2)

Q8JEE Main 2024 · 4 APR · SHIFT 2Easy

Equations of Kinematics

A bus moving along a straight highway with speed of $72\text{ km/h}$ is brought to a halt within $4\text{ s}$ after applying the brakes. The distance travelled by the bus during this time (Assume the retardation is uniform) is ________ $\text{m}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 40

$u = 72\text{ km/h} = 20\text{ m/s}$ , $v = 0$ , $t = 4\text{ s}$ .
For uniform retardation, $s = \frac{u + v}{2}t = \frac{20 + 0}{2} \times 4$
$s = 40\text{ m}$

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