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NEET 1991 (AIPMT) · Distance, Displacement & Average Speed

Distance, Displacement & Average Speed question from NEET 1991 (AIPMT)

Q22NEET 1991 · AIPMTEasy

Distance, Displacement & Average Speed

A bus travelling the first one-third distance at a speed of 10 km/h, the next one-third at 20 km/h and at last one-third at 60 km/h. The average speed of the bus is

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Answer: (c)

  1. Three equal distances dd: vavg=3dd/v1+d/v2+d/v3v_{avg} = \frac{3d}{d/v_1 + d/v_2 + d/v_3}.
  2. 110+120+160=6+3+160=16\frac{1}{10} + \frac{1}{20} + \frac{1}{60} = \frac{6 + 3 + 1}{60} = \frac{1}{6}
  3. vavg=3×6=18v_{avg} = 3 \times 6 = 18 km/h
  4. So the answer is (c) 18 km/h.
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