A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance C/2. The energy loss in the process after the charge is distributed between the two capacitors is: (a) 1/2CV₀² (b) 1/4CV₀² (c) 1/3CV₀² (d) 1/6CV₀²

Answer: (d). Energy loss on sharing Δ U = 1/2(C₁C₂)/(C₁ + C₂)(V₁ - V₂)² (C₁C₂)/(C₁ + C₂) = (C · C/2)/(3C/2) = C/3, V₁ - V₂ = V₀ Δ U = 1/6CV₀², so the answer is (d).

A capacitor C is fully charged with voltage V0. After disconnecting… | JEE Main 2020 (4 Sep, Shift 2)

Q26JEE Main 2020 · 4 SEP · SHIFT 2Easy

Charge Sharing & Loss of Energy

A capacitor C is fully charged with voltage V0. After disconnecting the voltage source, it is connected in parallel with another uncharged capacitor of capacitance $\frac{C}{2}$ . The energy loss in the process after the charge is distributed between the two capacitors is:

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Answer: (d)

Energy loss on sharing $\Delta U = \frac{1}{2}\frac{C_1C_2}{C_1 + C_2}(V_1 - V_2)^2$
$\frac{C_1C_2}{C_1 + C_2} = \frac{C \cdot C/2}{3C/2} = \frac{C}{3}$ , $V_1 - V_2 = V_0$
$\Delta U = \frac{1}{6}CV_0^2$ , so the answer is (d).

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Charge Sharing & Loss of Energy question from JEE Main 2020 (4 Sep, Shift 2)

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