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JEE Main 2023 (25 Jan, Shift 2) · Dielectrics

Dielectrics question from JEE Main 2023 (25 Jan, Shift 2)

Q55JEE Main 2023 · 25 JAN · SHIFT 2Easy

Dielectrics

A capacitor has capacitance 5μ\muF when its parallel plates are separated by air medium of thickness d. A slab of material of dielectric constant 1.5 having area equal to that of plates but thickness d2\frac{d}{2} is inserted between the plates. Capacitance of the capacitor in the presence of slab will be __________ μ\muF.

Numerical answer type. Work it out, then open the answer.

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Answer: 6

  1. Slab of thickness d2\frac{d}{2}: C′=2KCK+1C' = \frac{2KC}{K+1}.
  2. C′=2×1.5×52.5=6 μFC' = \frac{2 \times 1.5 \times 5}{2.5} = 6\ \mu\text{F}.
  3. So the capacitance is 6 μF6\ \mu\text{F}.
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