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MHT CET 2026 (16 Apr, Shift 2) · Dielectrics

Dielectrics question from MHT CET 2026 (16 Apr, Shift 2)

Q8MHT CET 2026 · 16 APR · SHIFT 2Easy

Dielectrics

A capacitor has capacity C when it's parallel plates are separated by air medium of thickness 'd'. A slab of material of dielectric constant K having area equal to that of plates but thickness d2\frac{d}{2} is inserted between the plates. Capacitance of the capacitor in the presence of slab will be

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Answer: (d)

  1. C′=ϵ0Ad−t+tKC' = \frac{\epsilon_0 A}{d - t + \frac{t}{K}} with t=d2t = \frac{d}{2}.
  2. d2+d2K=d(K+1)2K\frac{d}{2} + \frac{d}{2K} = \frac{d(K+1)}{2K}.
  3. C′=2KCK+1C' = \frac{2KC}{K+1}.
  4. So the answer is (d).
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