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NEET 2016 (Phase 1) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from NEET 2016 (Phase 1)

Q34NEET 2016 · PHASE 1Medium

Charge Sharing & Loss of Energy

A capacitor of 2 $\mu$ F is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is

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Answer: (b)

Fraction lost on sharing $= \frac{\Delta U}{U_i} = \frac{C_2}{C_1 + C_2}$ (from $U_f = \frac{Q^2}{2(C_1 + C_2)}$ ).
$\frac{8}{2 + 8} = 0.8$
So 80% is dissipated, answer (b).

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