A capacitor of 20 μ F is charged up to 500 V is connected in parallel with another capacitor of 10 μ F which is charged up to 200 V. Then, the common potential will be (a) 400 V (b) 200 V (c) 100 V (d) 50 V

Answer: (a). Common potential V = (C₁V₁ + C₂V₂)/(C₁ + C₂) V = (20 × 500 + 10 × 200)/(30) = (12000)/(30) = 400 V So the answer is (a) 400 V.

A capacitor of 20 μ F is charged up to 500 V is connected in parallel… | MHT CET 2026 (14 May, Shift 2)

Q1MHT CET 2026 · 14 MAY · SHIFT 2Easy

Charge Sharing & Loss of Energy

A capacitor of $20\ \mu$ F is charged up to $500$ V is connected in parallel with another capacitor of $10\ \mu$ F which is charged up to $200$ V. Then, the common potential will be

Show answer and solution

Answer: (a)

Common potential $V = \frac{C_1V_1 + C_2V_2}{C_1 + C_2}$
$V = \frac{20 \times 500 + 10 \times 200}{30} = \frac{12000}{30} = 400\ \text{V}$
So the answer is (a) $400$ V.

Report a mistake

More questions on Charge Sharing & Loss of Energy

A condenser of capacity C₁ is charged to potential V₁ and then disconnected. Uncharged…MHT CET 2026 (13 Apr, Shift 1)
A capacitor P with capacitance 10 × 10⁻⁶ F is fully charged with a potential difference…JEE Main 2026 (22 Jan, Shift 2)
Consider two uncharged capacitors of equal capacitance 200 pF. One of them is charged by…NEET 2026
A sphere of capacitance 100 pF is charged to a potential of 100 V. Another identical…JEE Main 2026 (6 Apr, Shift 2)
A parallel plate capacitor of capacitance 'C' is connected to a battery and charged to a…MHT CET 2026 (19 Apr, Shift 1)
Two capacitors of 100 and 50 are connected in parallel. If the potential difference…MHT CET 2025 (23 Apr, Shift 2)
Using a battery, a 100 pF capacitor is charged to 60 V and then the battery is removed…JEE Main 2025 (3 Apr, Shift 2)
A capacitor, C₁ = 6 is charged to a potential difference of V₀ = 5 V using a 5V battery…JEE Main 2025 (29 Jan, Shift 2)

Charge Sharing & Loss of Energy question from MHT CET 2026 (14 May, Shift 2)

More questions on Charge Sharing & Loss of Energy