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JEE Main 2022 (27 Jun, Shift 1) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from JEE Main 2022 (27 Jun, Shift 1)

Q19JEE Main 2022 · 27 JUN · SHIFT 1Easy

Charge Sharing & Loss of Energy

A capacitor of capacitance 50 pF is charged by 100 V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is ___________ nJ.

Numerical answer type. Work it out, then open the answer.

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Answer: 125

  1. For two identical capacitors, loss =14CV2= \frac{1}{4}CV^2.
  2. ΔU=14×50×10−12×1002=1.25×10−7\Delta U = \frac{1}{4} \times 50 \times 10^{-12} \times 100^2 = 1.25 \times 10^{-7} J
  3. Energy loss =125= 125 nJ
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