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JEE Main 2023 (11 Apr, Shift 2) · Parallel Plate Capacitor

Parallel Plate Capacitor question from JEE Main 2023 (11 Apr, Shift 2)

Q8JEE Main 2023 · 11 APR · SHIFT 2Easy

Parallel Plate Capacitor

A capacitor of capacitance CC is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is:

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Answer: (b)

  1. Gauss's law: ϕ=qencε0\phi = \frac{q_{enc}}{\varepsilon_0}.
  2. The surface encloses only the positive plate, charge Q=CVQ = CV.
  3. So the answer is (b) CVε0\frac{CV}{\varepsilon_0}.
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