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MHT CET 2025 (26 Apr, Shift 2) · Capacitance of a Conductor

Capacitance of a Conductor question from MHT CET 2025 (26 Apr, Shift 2)

Q4MHT CET 2025 · 26 APR · SHIFT 2Easy

Capacitance of a Conductor

A capacitor of unknown capacity is connected across a battery of V volt. The charge stored in it is Q coulomb. When potential across the capacitor is reduced by V1V_1 volt, the charge stored in it becomes Q1Q_1 coulomb. The potential V is

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Answer: (a)

  1. Capacitance is constant: C=QV=Q1V−V1C = \frac{Q}{V} = \frac{Q_1}{V - V_1}.
  2. Q(V−V1)=Q1V⇒V(Q−Q1)=QV1Q(V - V_1) = Q_1 V \Rightarrow V(Q - Q_1) = QV_1
  3. So the answer is (a) V=QV1Q−Q1V = \frac{QV_1}{Q - Q_1}.
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