A capacitor P with capacitance 10 × 10⁻⁶ F is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor P is connected across another capacitor Q with capacitance 20 × 10⁻⁶ F. The charge on capacitor Q when equilibrium is established will be α × 10⁻⁵ C (assume capacitor Q does not have any charge initially), the value of α is ______. Numerical answer type. Work it out, then open the answer.

Answer: 4. Q = 10 × 6 V = 60 μ C Common potential V = (60)/(10 + 20) = 2 V qQ = 20 × 2 V = 40 = 4 × 10⁻⁵ C So α = 4.

A capacitor P with capacitance 10 × 10⁻⁶ F is fully charged with a… | JEE Main 2026 (22 Jan, Shift 2)

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Charge Sharing & Loss of Energy

A capacitor $P$ with capacitance $10 \times 10^{-6}\text{ F}$ is fully charged with a potential difference of 6.0 V and disconnected from the battery. The charged capacitor $P$ is connected across another capacitor $Q$ with capacitance $20 \times 10^{-6}\text{ F}$ . The charge on capacitor $Q$ when equilibrium is established will be $\alpha \times 10^{-5}\text{ C}$ (assume capacitor $Q$ does not have any charge initially), the value of $\alpha$ is ______.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

$Q = 10\ \mu\text{F} \times 6\ \text{V} = 60\ \mu$ C
Common potential $V = \frac{60}{10 + 20} = 2$ V
$q_Q = 20\ \mu\text{F} \times 2\ \text{V} = 40\ \mu\text{C} = 4 \times 10^{-5}$ C
So $\alpha = 4$ .

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