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JEE Main 2014 (9 Apr, Shift 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from JEE Main 2014 (9 Apr, Shift 1)

Q65JEE Main 2014 · 9 APR · SHIFT 1Medium

Angle of Contact & Capillarity

A capillary tube is immersed vertically in water and the height of the water column is x. When this arrangement is taken into a mine of depth d, the height of the water column is y. If R is the radius of earth, the ratio $\frac{x}{y}$ is:

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Answer: (a)

$h \propto \dfrac{1}{g}$ , so $\dfrac{x}{y} = \dfrac{g'}{g}$ .
At depth $d$ : $g' = g\left(1 - \dfrac{d}{R}\right)$ .
$\dfrac{x}{y} = 1 - \dfrac{d}{R}$ .
So the answer is (a) $\left(1 - \dfrac{d}{R}\right)$ .

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