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JEE Main 2025 (7 Apr, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from JEE Main 2025 (7 Apr, Shift 2)

Q23JEE Main 2025 · 7 APR · SHIFT 2Medium

Angle of Contact & Capillarity

A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn/cm and glass water contact angle ≈ 0°) with 30° inclined with the vertical. The length of water risen in the capillary is _______ cm. (Take g=9.8g = 9.8 m/s2{}^{2})

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Answer: (a)

  1. Vertical rise h=2Trρg=2×0.0710−4×103×9.8=17 m≈14.29 cmh = \frac{2T}{r\rho g} = \frac{2 \times 0.07}{10^{-4} \times 10^3 \times 9.8} = \frac{1}{7}\text{ m} \approx 14.29\text{ cm}.
  2. Length along the tube inclined at 30∘30^\circ to the vertical: l=hcos⁡30∘=14.290.866l = \frac{h}{\cos 30^\circ} = \frac{14.29}{0.866}
  3. l≈16.5 cm≈825 cml \approx 16.5\text{ cm} \approx \frac{82}{5}\text{ cm}
  4. So the answer is (a) 825\frac{82}{5}.
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