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NEET 2020 (Phase 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from NEET 2020 (Phase 1)

Q59NEET 2020 · PHASE 1Medium

Angle of Contact & Capillarity

A capillary tube of radius r is immersed in water and water rises in it to a height h. The mass of the water in the capillary is 5 g. Another capillary tube of radius 2r is immersed in water. The mass of water that will rise in this tube is:

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Answer: (b)

Capillary rise $h = \dfrac{2T\cos\theta}{r\rho g}$ , so $h \propto \dfrac{1}{r}$ .
Mass raised $m = \pi r^2 h \rho \propto r^2 \cdot \dfrac{1}{r} = r$ .
Radius doubled $\Rightarrow m' = 2m = 2 \times 5 = 10$ g.
So the answer is (b) $10.0$ g.

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