A car covers AB distance with first one-third at velocity v1 ms ⁻¹, second one-third at v2 ms ⁻¹ and last one-third at v3 ms ⁻¹. If v3 = 3v1, v2 = 2v1 and v1 = 11 ms ⁻¹ then the average velocity of the car is _____________ ms______1. Numerical answer type. Work it out, then open the answer.

Answer: 18. Three equal parts d: vavg = (3d)/(d/v₁ + d/v₂ + d/v₃). v₁ = 11, v₂ = 22, v₃ = 33 m/s 1/11 + 1/22 + 1/33 = (6 + 3 + 2)/(66) = 1/6 vavg = 3 × 6 = 18 m/s

A car covers AB distance with first one-third at velocity v1 ms ⁻¹… | JEE Main 2022 (28 Jun, Shift 2)

Q15JEE Main 2022 · 28 JUN · SHIFT 2Easy

Distance, Displacement & Average Speed

A car covers AB distance with first one-third at velocity v1 ms ${}^{-1}$ , second one-third at v2 ms ${}^{-1}$ and last one-third at v3 ms ${}^{-1}$ . If v3 = 3v1, v2 = 2v1 and v1 = 11 ms ${}^{-1}$ then the average velocity of the car is _____________ ms______1.

Numerical answer type. Work it out, then open the answer.

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Answer: 18

Three equal parts $d$ : $v_{avg} = \frac{3d}{d/v_1 + d/v_2 + d/v_3}$ .
$v_1 = 11,\ v_2 = 22,\ v_3 = 33$ m/s
$\frac{1}{11} + \frac{1}{22} + \frac{1}{33} = \frac{6 + 3 + 2}{66} = \frac{1}{6}$
$v_{avg} = 3 \times 6 = 18$ m/s

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Distance, Displacement & Average Speed question from JEE Main 2022 (28 Jun, Shift 2)

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