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NEET 1990 (AIPMT) · Distance, Displacement & Average Speed

Distance, Displacement & Average Speed question from NEET 1990 (AIPMT)

Q23NEET 1990 · AIPMTEasy

Distance, Displacement & Average Speed

A car covers the first half of the distance between two places at 40 km/h and another half at 60 km/h. The average speed of the car is

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Answer: (b)

  1. Equal distances: vavg=2v1v2v1+v2v_{avg} = \frac{2v_1 v_2}{v_1 + v_2}.
  2. vavg=2(40)(60)100=48v_{avg} = \frac{2(40)(60)}{100} = 48 km/h
  3. So the answer is (b) 48 km/h.
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