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NEET 1988 (AIPMT) · Equations of Kinematics

Equations of Kinematics question from NEET 1988 (AIPMT)

Q46NEET 1988 · AIPMTEasy

Equations of Kinematics

A car is moving along a straight road with a uniform acceleration. It passes through two points PP and QQ separated by a distance with velocity 30 km/h and 40 km/h respectively. The velocity of the car midway between PP and QQ is

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Answer: (c)

  1. Midpoint velocity: vm=vP2+vQ22v_m = \sqrt{\frac{v_P^2 + v_Q^2}{2}}
  2. vm=302+4022=1250v_m = \sqrt{\frac{30^2 + 40^2}{2}} = \sqrt{1250}
  3. vm=252 km/hv_m = 25\sqrt{2}\text{ km/h}. So the answer is (c).
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