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JEE Main 2023 (25 Jan, Shift 1) · Banking of Roads & Bridges

Banking of Roads & Bridges question from JEE Main 2023 (25 Jan, Shift 1)

Q10JEE Main 2023 · 25 JAN · SHIFT 1Easy

Banking of Roads & Bridges

A car is moving with a constant speed of 20 m/s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be: (Take g = 10 m/s2^{2})

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Answer: (c)

  1. tan⁡θ=v2rg\tan\theta = \frac{v^2}{rg}
  2. tan⁡θ=40040×10=1⇒θ=45∘\tan\theta = \frac{400}{40 \times 10} = 1 \Rightarrow \theta = 45^\circ
  3. So the answer is (c) π4\frac{\pi}{4}.
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