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JEE Main 2017 (9 Apr, Shift 1) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2017 (9 Apr, Shift 1)

Q33JEE Main 2017 · 9 APR · SHIFT 1Easy

Equations of Kinematics

A car is standing 200 m behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration 2 m/s2 and the car has acceleration 4 m/s2. The car will catch up with the bus after a time of:

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Answer: (c)

  1. Relative to the bus, the car starts from rest with arel=4−2=2 m/s2a_{rel} = 4 - 2 = 2\text{ m/s}^2 and must cover 200 m.
  2. 200=12(2)t2⇒t2=200200 = \frac{1}{2}(2)t^2 \Rightarrow t^2 = 200
  3. t=102 st = 10\sqrt{2}\text{ s}
  4. So the answer is (c) 102 s10\sqrt{2}\text{ s}.
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