A car is travelling at 40 m/s on a circular path of radius 40 m. It is increasing its speed at the rate of 2 m/s ². Its net acceleration is (in m/s ²) nearly (a) 4 m/s ² (b) 8 m/s ² (c) 16 m/s ² (d) 40 m/s ²

Answer: (d). Radial: ar = v²/r = (1600)/(40) = 40 m/s ²; tangential at = 2 m/s ². a = √(ar² + at²) = √(1600 + 4) ≈ 40 m/s ² So the answer is (d) 40 m/s ².

A car is travelling at 40 m/s on a circular path of radius 40 m. It… | MHT CET 2026 (20 Apr, Shift 2)

Q1MHT CET 2026 · 20 APR · SHIFT 2Easy

Non-Uniform Circular Motion

A car is travelling at 40 m/s on a circular path of radius 40 m. It is increasing its speed at the rate of $2$ m/s $^{2}$ . Its net acceleration is (in m/s $^{2}$ ) nearly

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Answer: (d)

Radial: $a_r = \frac{v^2}{r} = \frac{1600}{40} = 40$ m/s $^2$ ; tangential $a_t = 2$ m/s $^2$ .
$a = \sqrt{a_r^2 + a_t^2} = \sqrt{1600 + 4} \approx 40$ m/s $^2$
So the answer is (d) 40 m/s $^2$ .

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