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NEET 1991 (AIPMT) · Distance, Displacement & Average Speed

Distance, Displacement & Average Speed question from NEET 1991 (AIPMT)

Q21NEET 1991 · AIPMTEasy

Distance, Displacement & Average Speed

A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed vv. The average speed is 48 km/h. The value of vv is

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Answer: (b)

  1. Equal distances: vavg=2v1vv1+vv_{avg} = \frac{2v_1 v}{v_1 + v}.
  2. 48=2(40)v40+v⇒1920+48v=80v48 = \frac{2(40)v}{40 + v} \Rightarrow 1920 + 48v = 80v
  3. 32v=1920⇒v=6032v = 1920 \Rightarrow v = 60 km/h
  4. So the answer is (b) 60 km/h.
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