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NEET 2007 (AIPMT) · Distance, Displacement & Average Speed

Distance, Displacement & Average Speed question from NEET 2007 (AIPMT)

Q19NEET 2007 · AIPMTEasy

Distance, Displacement & Average Speed

A car moves from X to Y with a uniform speed vu and returns to X with a uniform speed vd. The average speed for this round trip is

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Answer: (d)

  1. XY and YX are equal distances dd, so total distance =2d= 2d.
  2. Total time =dvu+dvd= \frac{d}{v_u} + \frac{d}{v_d}
  3. vavg=2dd/vu+d/vd=2vuvdvu+vdv_{avg} = \frac{2d}{d/v_u + d/v_d} = \frac{2v_u v_d}{v_u + v_d}
  4. So the answer is (d).
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