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JEE Main 2003 (AIEEE) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2003 (AIEEE)

Q39JEE Main 2003 · AIEEEEasy

Equations of Kinematics

A car, moving with a speed of 50 km/hr, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/hr, the minimum stopping distance is

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Answer: (c)

  1. For the same retardation, s∝u2s \propto u^2.
  2. Speed doubles (50 to 100 km/h), so s′=4×6=24 ms' = 4 \times 6 = 24\text{ m}.
  3. So the answer is (c) 24 m.
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