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JEE Main 2026 (8 Apr, Shift 2) · Banking of Roads & Bridges

Banking of Roads & Bridges question from JEE Main 2026 (8 Apr, Shift 2)

Q1JEE Main 2026 · 8 APR · SHIFT 2Easy

Banking of Roads & Bridges

A car moving with a speed of 54 km/h54\text{ km/h} takes a turn of radius 20 m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take g=10 m/s2g = 10\text{ m/s}^2)

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Answer: (c)

  1. v=54v = 54 km/h =15= 15 m/s.
  2. tan⁡θ=v2rg=22520×10=1.125\tan\theta = \frac{v^2}{rg} = \frac{225}{20 \times 10} = 1.125
  3. So the answer is (c) tan⁡−1(1.125)\tan^{-1}(1.125).
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