Physics Circle home Student Login

Home›Chapters›Rotational Motion PYQs›Rotational Kinematics & Dynamics›Question 70

NEET 2012 (AIPMT, Mains) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from NEET 2012 (AIPMT, Mains)

Q70NEET 2012 · AIPMT · MAINSEasy

Rotational Kinematics & Dynamics

A car of mass m is moving on a level circular track of radius R. If μ\mus represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by

Show answer and solution

Answer: (d)

  1. On a level track, static friction supplies the centripetal force: mv2R≤μsmg\frac{mv^2}{R} \le \mu_s mg.
  2. vmax2=μsRgv_{max}^2 = \mu_s Rg (mass cancels).
  3. So the answer is (d) μsRg\sqrt{\mu_s Rg}.
Report a mistake

More questions on Rotational Kinematics & Dynamics