Student Login

Home›Chapters›Motion in One Dimension PYQs›Equations of Kinematics›Question 1

MHT CET 2026 (11 Apr, Shift 1) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2026 (11 Apr, Shift 1)

Q1MHT CET 2026 · 11 APR · SHIFT 1Medium

Equations of Kinematics

A car passes three points A, B and C at $3$ m/s, $6$ m/s and $9$ m/s respectively in a straight line with uniform acceleration. If distance $AB = 60$ m then find the distance BC.

Show answer and solution

Answer: (a)

Use $v^2 - u^2 = 2as$ on each part (same $a$ ).
AB: $6^2 - 3^2 = 27 = 2a(60)$
BC: $9^2 - 6^2 = 45 = 2a(BC)$
Dividing: $\frac{BC}{60} = \frac{45}{27} \Rightarrow BC = 100\text{ m}$
So the answer is (a) $100$ m.

Report a mistake

More questions on Equations of Kinematics

A body moving with uniform acceleration travel 16 m in the third second of its motion and…MHT CET 2026 (20 May, Shift 1)
Two bodies A and B move in same straight line starting from same position. Body A moves…MHT CET 2025 (20 Apr, Shift 2)
A car moving at a speed ' v ' is stopped in a certain distance when the brakes produce a…MHT CET 2025 (26 Apr, Shift 2)
A body starts from rest and moves with a uniform acceleration. The ratio of the distance…MHT CET 2025 (21 Apr, Shift 2)
A body travelling with uniform acceleration crosses two points A and B with velocities 20…MHT CET 2024 (16 May, Shift 2)
Two cars are travelling towards each other at speed of 20 m s⁻¹ each. When the cars are…JEE Main 2024 (9 Apr, Shift 2)
A bus moving along a straight highway with speed of 72 km/h is brought to a halt within 4…JEE Main 2024 (4 Apr, Shift 2)
A body travels 102.5 m in n th second and 115.0 m in (n+2) th second. The acceleration is:JEE Main 2024 (4 Apr, Shift 1)