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JEE Main 2019 (9 Jan, Shift 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2019 (9 Jan, Shift 2)

Q45JEE Main 2019 · 9 JAN · SHIFT 2Easy

Ohm's Law, Resistivity & Temperature

A carbon resistance has a following colour code. What is the value of the resistance?

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Answer: (a)

Green = 5, Orange = 3, Yellow = multiplier $10^4$ , Gold = $\pm 5\%$ .
$R = 53 \times 10^4 = 530\text{ k}\Omega$
So the answer is (a) $530\text{ k}\Omega \pm 5\%$ .

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