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NEET 2015 (AIPMT, Cancelled Paper) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2015 (AIPMT, Cancelled Paper)

Q70NEET 2015 · AIPMT · CANCELLED PAPERMedium

Heat Engines, Refrigerators & Second Law

A Carnot engine, having an efficiency of $\eta = \frac{1}{10}$ as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

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Answer: (a)

Carnot refrigerator: $\beta = \frac{1-\eta}{\eta} = \frac{1 - 1/10}{1/10} = 9$ .
$Q_2 = \beta W = 9 \times 10 = 90$ J
So the answer is (a) 90 J.

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