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MHT CET 2024 (4 May, Shift 1) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from MHT CET 2024 (4 May, Shift 1)

Q17MHT CET 2024 · 4 MAY · SHIFT 1Medium

Heat Engines, Refrigerators & Second Law

A carnot engine, whose efficiency is $40\%$ takes heat from a source maintained at temperature 600 K. It is desired to have an efficiency $60\%$ , then the intake temperature for the same exhaust (sink) temperature should be

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Answer: (c)

$\eta = 1 - \frac{T_2}{T_1}$ : $T_2 = (1 - 0.4)(600) = 360\text{ K}$ .
For $\eta = 0.6$ with same sink: $T_1' = \frac{T_2}{1 - 0.6} = \frac{360}{0.4} = 900\text{ K}$ .
So the answer is (c) 900 K.

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