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MHT CET 2026 (17 Apr, Shift 1) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from MHT CET 2026 (17 Apr, Shift 1)

Q5MHT CET 2026 · 17 APR · SHIFT 1Medium

Heat Engines, Refrigerators & Second Law

A Carnot engine, whose efficiency is 40% takes heat from a source maintained at temperature 600K. To have an efficiency 60%, the intake temperature for the same exhaust temperature should be

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Answer: (b)

  1. 0.4=1−T2600⇒T2=3600.4 = 1 - \frac{T_2}{600} \Rightarrow T_2 = 360 K
  2. 0.6=1−360T1′⇒T1′=3600.4=9000.6 = 1 - \frac{360}{T_1'} \Rightarrow T_1' = \frac{360}{0.4} = 900 K
  3. So the answer is (b) 900 K.
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