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JEE Main 2012 (AIEEE) · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from JEE Main 2012 (AIEEE)

Q74JEE Main 2012 · AIEEEMedium

Heat Engines, Refrigerators & Second Law

A Carnot engine, whose efficiency is $40\%$ , takes in heat from a source maintained at a temperature of $500\ K.$ It is desired to have an engine of efficiency $60\%.$ Then, the intake temperature for the same exhaust (sink) temperature must be:

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Answer: (c)

$T_2 = (1 - 0.4)(500) = 300\text{ K}$
For $\eta = 0.6$ : $T_1' = \frac{300}{0.4} = 750\text{ K}$
So the answer is (c) $750\ K$ .

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