Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Potentiometer›Question 84

NEET 2008 (AIPMT) · Potentiometer

Potentiometer question from NEET 2008 (AIPMT)

Q84NEET 2008 · AIPMTMedium

Potentiometer

A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and without being short circuited through a resistance of 10 Ω\Omega. Its internal resistance is

Show answer and solution

Answer: (c)

  1. Open-circuit length is the larger one: l0=110l_0 = 110 cm; shunted by 10 Ω10\ \Omega: l=100l = 100 cm.
  2. r=Rl0−ll=10×110−100100r = R\dfrac{l_0-l}{l} = 10\times\dfrac{110-100}{100}
  3. r=1 Ωr = 1\ \Omega
  4. So the answer is (c) 1.0 ohm.
Report a mistake

More questions on Potentiometer