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NEET 2000 (AIPMT) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from NEET 2000 (AIPMT)

Q52NEET 2000 · AIPMTEasy

Cells: EMF, Internal Resistance & Combinations

A cell has an emf 1.5 V1.5\text{ V}. When connected across an external resistance of 2 Ω2\ \Omega, the terminal potential difference falls to 1.0 V1.0\text{ V}. The internal resistance of the cell is

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Answer: (c)

  1. I=VR=1.02=0.5 AI = \frac{V}{R} = \frac{1.0}{2} = 0.5\text{ A}
  2. r=E−VI=0.50.5=1.0 Ωr = \frac{E - V}{I} = \frac{0.5}{0.5} = 1.0\ \Omega. So the answer is (c).
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