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JEE Main 2019 (8 Apr, Shift 2) · Cells: EMF, Internal Resistance & Combinations

Cells: EMF, Internal Resistance & Combinations question from JEE Main 2019 (8 Apr, Shift 2)

Q32JEE Main 2019 · 8 APR · SHIFT 2Easy

Cells: EMF, Internal Resistance & Combinations

A cell of internal resistance r drives current through an external resistance R. The power delivered by the cell to the external resistance will be maximum when :-

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Answer: (b)

$P = \frac{E^2 R}{(R + r)^2}$ is maximum when $\frac{dP}{dR} = 0 \Rightarrow R = r$ .
So the answer is (b) $R = r$ .

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