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NEET 1990 (AIPMT) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from NEET 1990 (AIPMT)

Q74NEET 1990 · AIPMTEasy

Thermometry & Thermal Expansion

A Centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers 140∘F140^\circ\text{F}. What is the fall in temperature as registered by the centigrade thermometer?

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Answer: (c)

  1. Boiling water: 100∘100^\circC. At 140∘140^\circF: C=59(140−32)=60∘C=\frac{5}{9}(140-32)=60^\circC.
  2. Fall =100−60=40∘=100-60=40^\circC
  3. So the answer is (c) 40∘40^\circC.
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