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JEE Main 2022 (25 Jul, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2022 (25 Jul, Shift 1)

Q169JEE Main 2022 · 25 JUL · SHIFT 1Medium

Thermodynamic Processes

A certain amount of gas of volume VV at 27∘C27^\circ\text{C} temperature and pressure 2×107 Nm−22 \times 10^{7}\text{ Nm}^{-2} expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use γ=1.5)\gamma = 1.5):

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Answer: (b)

  1. Isothermal, volume doubles: P1=2×1072=107P_1 = \frac{2\times10^7}{2} = 10^7 Pa.
  2. Adiabatic, volume doubles again: P2=10721.5=1072.828P_2 = \frac{10^7}{2^{1.5}} = \frac{10^7}{2.828}
  3. P2≈3.536×106P_2 \approx 3.536\times10^6 Pa
  4. So the answer is (b) 3.536×1063.536\times10^6 Pa.
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