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Nuclear Fission & Fusion question from NEET 2013

Q26NEET 2013Easy

Nuclear Fission & Fusion

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

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Answer: (a)

Energy released $= \Delta m \times 931 = 0.02866 \times 931 \approx 26.7\text{ MeV}$ for $4\,{}^1\text{H} \to {}^4\text{He}$ .
The reacting mass is about $4\text{ u}$ , so energy per u $= \dfrac{26.7}{4} \approx 6.675\text{ MeV}$ .
So the answer is (a) $6.675\text{ MeV}$ .

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