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JEE Main 2021 (20 Jul, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from JEE Main 2021 (20 Jul, Shift 2)

Q111JEE Main 2021 · 20 JUL · SHIFT 2Medium

Photoelectric Effect: Einstein's Equation

A certain metallic surface is illuminated by monochromatic radiation of wavelength λ\lambda. The stopping potential for photoelectric current for this radiation is 3V0. If the same surface is illuminated with a radiation of wavelength 2λ\lambda, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is ____________ λ\lambda.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. Einstein: hcλ=ϕ+eVs\frac{hc}{\lambda} = \phi + eV_s; write A=hcλA = \frac{hc}{\lambda}.
  2. A−ϕ=3eV0A - \phi = 3eV_0 and A2−ϕ=eV0\frac{A}{2} - \phi = eV_0
  3. Subtract: A2=2eV0⇒A=4eV0, ϕ=eV0=A4\frac{A}{2} = 2eV_0 \Rightarrow A = 4eV_0,\ \phi = eV_0 = \frac{A}{4}
  4. λ0=hcϕ=4λ\lambda_0 = \frac{hc}{\phi} = 4\lambda
  5. So the answer is 4, i.e. λ0=4λ\lambda_0 = 4\lambda.
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