A charge moves in a circular path perpendicular to a magnetic field. The time period of revolution is independent of (a) mass of the particle (b) velocity of the particle (c) magnetic field (d) charge

Answer: (b). r = mv/qB, so T = (2π r)/(v) = (2π m)/(qB). T depends on m, q, B but not on velocity. So the answer is (b) velocity of the particle.

A charge moves in a circular path perpendicular to a magnetic field… | MHT CET 2026 (15 Apr, Shift 2)

Q6MHT CET 2026 · 15 APR · SHIFT 2Easy

Moving Charge in a Magnetic Field

A charge moves in a circular path perpendicular to a magnetic field. The time period of revolution is independent of

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Answer: (b)

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