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JEE Main 2022 (27 Jul, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2022 (27 Jul, Shift 2)

Q44JEE Main 2022 · 27 JUL · SHIFT 2Easy

Electric Charge & Coulomb's Law

A charge of $4\ \mu\text{C}$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:

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Answer: (b)

$F \propto q(Q-q)$ is maximum when $q = \dfrac{Q}{2}$ .
$q = \dfrac{4}{2} = 2\ \mu\text{C}$
So the answer is (b) $2\ \mu\text{C}$ and $2\ \mu\text{C}$ .

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