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MHT CET 2026 (13 Apr, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2026 (13 Apr, Shift 1)

Q4MHT CET 2026 · 13 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

A charge 'Q' C is placed at the centre of a cube. The electric flux through two opposite faces of the cube is

( $\epsilon_0$ = permittivity of free space)

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Answer: (b)

Total flux $= \dfrac{Q}{\varepsilon_0}$ , shared equally by 6 faces by symmetry: $\dfrac{Q}{6\varepsilon_0}$ per face.
Two faces: $2\times\dfrac{Q}{6\varepsilon_0} = \dfrac{Q}{3\varepsilon_0}$
So the answer is (b).

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