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JEE Main 2024 (4 Apr, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2024 (4 Apr, Shift 2)

Q44JEE Main 2024 · 4 APR · SHIFT 2Easy

Electric Flux & Gauss's Law

A charge $q$ is placed at the center of one of the surfaces of a cube. The flux linked with the cube is:

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Answer: (a)

A charge at the centre of a face is shared by two identical cubes on either side of that face.
Flux through this cube $= \dfrac{1}{2}\cdot\dfrac{q}{\epsilon_0} = \dfrac{q}{2\epsilon_0}$ .
So the answer is (a).

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