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JEE Main 2020 (6 Sep, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from JEE Main 2020 (6 Sep, Shift 2)

Q62JEE Main 2020 · 6 SEP · SHIFT 2Medium

Current Loop as a Magnetic Dipole

A charged particle going around in a circle can be considered to be a current loop. A particle of mass m carrying charge q is moving in a plane with speed v under the influence of magnetic field B⃗\vec{B}. The magnetic moment of this moving particle:

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Answer: (b)

  1. Radius r=mvqBr = \frac{mv}{qB}; equivalent current I=qv2πrI = \frac{qv}{2\pi r}.
  2. M=Iπr2=qvr2=qv2⋅mvqB=mv22BM = I\pi r^2 = \frac{qvr}{2} = \frac{qv}{2}\cdot\frac{mv}{qB} = \frac{mv^2}{2B}
  3. The induced moment always opposes B⃗\vec{B} (for either sign of qq), so M⃗=−mv22BB^=−mv2B⃗2B2\vec{M} = -\frac{mv^2}{2B}\hat{B} = -\frac{mv^2\vec{B}}{2B^2}.
  4. So the answer is (b).
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