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MHT CET 2024 (4 May, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from MHT CET 2024 (4 May, Shift 1)

Q35MHT CET 2024 · 4 MAY · SHIFT 1Medium

Moving Charge in a Magnetic Field

A charged particle of charge ' $q$ ' is accelerated by a potential difference ' $V$ ' enters a region of uniform magnetic field ' $B$ ' at right angles to the direction of field. The charged particle completes semicircle of radius ' $r$ ' inside magnetic field. The mass of the charged particle is

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Answer: (a)

After acceleration: $\dfrac{p^2}{2m} = qV$ ; in the field $p = qBr$ .
$m = \dfrac{q^2B^2r^2}{2qV} = \dfrac{r^2qB^2}{2V}$
So the answer is (a) $\frac{r^2qB^2}{2V}$ .

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