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JEE Main 2005 (AIEEE) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from JEE Main 2005 (AIEEE)

Q117JEE Main 2005 · AIEEEEasy

Moving Charge in a Magnetic Field

A charged particle of mass $m$ and charge $q$ travels on a circular path of radius $r$ that is perpendicular to a magnetic field $B.$ The time taken by the particle to complete one revolution is

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Answer: (c)

$qvB = \dfrac{mv^2}{r} \Rightarrow v = \dfrac{qBr}{m}$
$T = \dfrac{2\pi r}{v} = \dfrac{2\pi m}{qB}$
So the answer is (c) $\dfrac{2\pi m}{qB}$ .

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