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MHT CET 2025 (19 Apr, Shift 2) · Motion of Charges in an Electric Field

Motion of Charges in an Electric Field question from MHT CET 2025 (19 Apr, Shift 2)

Q4MHT CET 2025 · 19 APR · SHIFT 2Easy

Motion of Charges in an Electric Field

A charged particle of mass ' mm ' and charge ' qq ' is at rest. It is acce:lerated in a uniform electric field of intensity ' EE ': for time ' tt '. The kinetic energy of the particles after time tt is

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Answer: (b)

  1. a=qEma = \frac{qE}{m}, so from rest v=at=qEtmv = at = \frac{qEt}{m}.
  2. K=12mv2=12mq2E2t2m2=E2q2t22mK = \frac{1}{2}mv^2 = \frac{1}{2}m\frac{q^2E^2t^2}{m^2} = \frac{E^2q^2t^2}{2m}
  3. So the answer is (b).
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