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MHT CET 2026 (12 May, Shift 1) · Moving Charge in a Magnetic Field

Moving Charge in a Magnetic Field question from MHT CET 2026 (12 May, Shift 1)

Q5MHT CET 2026 · 12 MAY · SHIFT 1Easy

Moving Charge in a Magnetic Field

A charged particle of mass $m$ and charge $q$ travels on a circular path, (of radius $5$ unit) is perpendicular to a magnetic field $B$ . The time taken by a particle to complete $10$ revolutions is

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Answer: (b)

Time period $T = \frac{2\pi m}{qB}$ , independent of radius.
Time for 10 revolutions $= 10T = \frac{20\pi m}{qB}$
So the answer is (b) $20\pi m/qB$ .

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