A charged particle q is accelerated by a potential difference of V… | MHT CET 2026 (13 Apr, Shift 2)

Q11MHT CET 2026 · 13 APR · SHIFT 2Medium

Moving Charge in a Magnetic Field

A charged particle $q$ is accelerated by a potential difference of $V$ enters a region of uniform magnetic field of induction $B$ at right angles to the direction of the field. The charged particle completes semi circle of the radius $r$ inside the magnetic field. The mass of the charged particle is (all quantities are in SI units)

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Answer: (b)

After acceleration: $\dfrac{p^2}{2m} = qV$ .
In the field: $r = \dfrac{p}{qB} \Rightarrow p = qBr$ .
$m = \dfrac{p^2}{2qV} = \dfrac{q^2B^2r^2}{2qV} = \dfrac{qr^2B^2}{2V}$
So the answer is (b) $qr^2B^2/2V$ .

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